Any math hats here?

24

Comments

  • Collin wrote:
    5x^2 + 15x^3/10x
    =>

    5x^2/10x + 15x^3/10x


    You should be able to solve this using the same method.

    You can post your answers, and I'll check them ;)

    Good luck.

    (x+3x²)/2 or (x(1+3x))/2
  • Murderers.
    Murderers. Posts: 1,382
    Collin wrote:
    What answers did you get?
    14a^2b^3 / 2ab^2 = 7ab

    5x^2 + 15x^3 / 10x = x + 3x^2 / 2

    3x^3 y^2 + 21x^2y / 2x^2 y^2 = 3(xy+7) / 2y
    What the fuck is this world?
  • chadwick
    chadwick up my ass Posts: 21,157
    5x squared + 15x cubed
    10x

    is this answer 3377.5
    or is it
    4.5


    or am i a fucking igit?

    something is a miss 'round here with my figuring
    for poetry through the ceiling. ISBN: 1 4241 8840 7

    "Hear me, my chiefs!
    I am tired; my heart is
    sick and sad. From where
    the sun stands I will fight
    no more forever."

    Chief Joseph - Nez Perce
  • Collin
    Collin Posts: 4,931
    Murderers wrote:
    14a^2b^3 / 2ab^2 = 7ab

    5x^2 + 15x^3 / 10x = x + 3x^2 / 2

    3x^3 y^2 + 21x^2y / 2x^2 y^2 = 3(xy+7) / 2y

    Correct, all of them! :D
    THANK YOU, LOSTDAWG!


    naděje umírá poslední
  • 1 2 3 4 5 6 7 8 9 10
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  • Murderers.
    Murderers. Posts: 1,382
    Collin wrote:
    Correct, all of them! :D
    :D!
    1 2 3 4 5 6 7 8 9 10
    I wish it was that simple.
    What the fuck is this world?
  • JaneNY
    JaneNY Posts: 4,438
    chadwick wrote:
    5x squared + 15x cubed
    10x

    is this answer 3377.5
    or is it
    4.5


    or am i a fucking igit?

    something is a miss 'round here with my figuring

    No, you can't get a numerical answer, because these aren't equations. They are simply expressions, and all you can do is simplify them. All you can simplify it to is
    x(1+3x)/2 as someone mentioned, but since you don't know a value for 'x' you can't take it any further.
    R.i.p. Rigoberto Alpizar.
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  • PearlJamaholic
    PearlJamaholic Posts: 2,019
    i have a math test tuesday, anyone wanna take it for me? something about logs and stuff. i failed the last two im really hoping for a miracle this time.
  • chadwick
    chadwick up my ass Posts: 21,157
    JaneNY wrote:
    No, you can't get a numerical answer, because these aren't equations. They are simply expressions, and all you can do is simplify them. All you can simplify it to is
    x(1+3x)/2 as someone mentioned, but since you don't know a value for 'x' you can't take it any further.

    yeah that's right.
    equations aren't expressions.
    thank you kindly.
    for poetry through the ceiling. ISBN: 1 4241 8840 7

    "Hear me, my chiefs!
    I am tired; my heart is
    sick and sad. From where
    the sun stands I will fight
    no more forever."

    Chief Joseph - Nez Perce
  • Collin
    Collin Posts: 4,931
    I actually always sucked at maths. I was surprised I could do this. But then again, my brother's a math teacher and my father an evil and mad mathematician who's been building several doomsday devices.
    THANK YOU, LOSTDAWG!


    naděje umírá poslední
  • Murderers.
    Murderers. Posts: 1,382
    Collin wrote:
    I actually always sucked at maths. I was surprised I could do this. But then again, my brother's a math teacher and my father an evil and mad mathematician who's been building several doomsday devices.
    I want to think you're joking for the later, but somehow I don't think you are....
    What the fuck is this world?
  • Collin
    Collin Posts: 4,931
    Murderers wrote:
    I want to think you're joking for the later, but somehow I don't think you are....

    He's not an mathematician. He's a mechanical engineer.
    THANK YOU, LOSTDAWG!


    naděje umírá poslední
  • stuckinline
    stuckinline Posts: 3,407
    Murderers wrote:
    14a^2b^3 / 2ab^2 = 7ab

    5x^2 + 15x^3 / 10x = x + 3x^2 / 2

    3x^3 y^2 + 21x^2y / 2x^2 y^2 = 3(xy+7) / 2y
    these are the correct answers
  • Red Lukin
    Red Lukin Canada Posts: 2,994
    ^^^
    I concur (but wow that's been a while)
  • westsidepie
    westsidepie Posts: 627
    JaneNY wrote:
    No, you can't get a numerical answer, because these aren't equations. They are simply expressions, and all you can do is simplify them. All you can simplify it to is
    x(1+3x)/2 as someone mentioned, but since you don't know a value for 'x' you can't take it any further.

    All correct, and the answers that have been given are all correct. I just wanted to add a slightly different method to get at the answers that will help you later. You can factor each expression in the fraction and then cancel. For example

    12x^2 / 6x^3 factored becomes 6x^2(2) / 6x^2(x). The 6x^2 cancels and you are left with 2/x.

    14a^2b^3 / 2ab^2 factored becomes 2ab^2(7ab) /2ab^2. The 2ab^2 cancel and you are left with 7ab.
    To pie I will reply
    But mr. justam
    is who I am

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  • Murderers.
    Murderers. Posts: 1,382
    I have a new one for people: x+5/3 = 5-3(x+1)/2

    It's simple. I just don't know how to expand out the bracket on the right hand side of the equals.
    What the fuck is this world?
  • Murderers wrote:
    I need to solve these problems:

    untitled-3.jpg

    It doesn't matter if you can't do it.

    An explanation would be much appreciated too.

    oops nevermind just saw that you already got help.
  • BinFrog
    BinFrog MA Posts: 7,314
    JaneNY wrote:
    No, you can't get a numerical answer, because these aren't equations. They are simply expressions, and all you can do is simplify them. All you can simplify it to is
    x(1+3x)/2 as someone mentioned, but since you don't know a value for 'x' you can't take it any further.



    That is exactly what I was going to say.
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  • BinFrog wrote:
    That is exactly what I was going to say.

    yeah that's why I was going to ask what it was he was actually supposed to do with these expressions.
  • markymark550
    markymark550 Columbia, SC Posts: 5,224
    Murderers wrote:
    I have a new one for people: x+5/3 = 5-3(x+1)/2

    It's simple. I just don't know how to expand out the bracket on the right hand side of the equals.
    on the right side, distribute the -3 over the (x+1) and then solve the equation for x

    if I've done it correctly, x = -4/11